📋 MOCK TEST – SET 16
WBSSC Group C (Clerk) Written Exam Preparation
Total: 60 Questions | GA: 20 | English: 10 | Reasoning: 10 | Arithmetic: 20 | Click any option to see answer & explanation
SECTION A: GENERAL AWARENESS (Q.1–Q.20) — 20 Marks
Q.1. NEP 2020 proposes the establishment of a ‘National Assessment Centre’. It will be called: NEP 2020
Answer: (2) PARAKH
NEP 2020 proposes PARAKH — Performance Assessment, Review, and Analysis of Knowledge for Holistic Development — as a single National Assessment Centre. PARAKH will set norms, standards, and guidelines for student assessment and evaluation for all school boards and institutions. It aims to shift from rote learning to competency-based assessment. PARAKH was established by NCERT in 2023. The National Testing Agency (NTA) conducts higher education entrance exams like JEE, NEET.
NEP 2020 proposes PARAKH — Performance Assessment, Review, and Analysis of Knowledge for Holistic Development — as a single National Assessment Centre. PARAKH will set norms, standards, and guidelines for student assessment and evaluation for all school boards and institutions. It aims to shift from rote learning to competency-based assessment. PARAKH was established by NCERT in 2023. The National Testing Agency (NTA) conducts higher education entrance exams like JEE, NEET.
Q.2. NEP 2020 mandates that all students must study at least one ‘regional language’ from: NEP 2020
Answer: (2) Class 6 onwards
NEP 2020 recommends a three-language formula: students should study three languages from Class 6 onwards — two of which must be native Indian languages (e.g., Hindi, regional language, Sanskrit). The formula is flexible, but no language imposition. From Class 1–5, focus on mother tongue/local language + one other language. The policy aims to promote multilingualism without compromising proficiency in any language. Classical languages (Tamil, Sanskrit, Telugu, Kannada, Malayalam, Odia) will get special emphasis.
NEP 2020 recommends a three-language formula: students should study three languages from Class 6 onwards — two of which must be native Indian languages (e.g., Hindi, regional language, Sanskrit). The formula is flexible, but no language imposition. From Class 1–5, focus on mother tongue/local language + one other language. The policy aims to promote multilingualism without compromising proficiency in any language. Classical languages (Tamil, Sanskrit, Telugu, Kannada, Malayalam, Odia) will get special emphasis.
Q.3. NEP 2020 aims to phase out which type of institutions over time? NEP 2020
Answer: (1) Standalone teacher education institutions
NEP 2020 calls for phasing out standalone teacher education institutions (single-subject B.Ed./D.El.Ed. colleges). Instead, teacher education will be integrated into multidisciplinary colleges and universities. By 2030, minimum qualification for teaching will be a 4-year integrated B.Ed.. Stand-alone institutions lack quality and research focus. The policy aims to improve teacher training quality through integration with broader academic ecosystems.
NEP 2020 calls for phasing out standalone teacher education institutions (single-subject B.Ed./D.El.Ed. colleges). Instead, teacher education will be integrated into multidisciplinary colleges and universities. By 2030, minimum qualification for teaching will be a 4-year integrated B.Ed.. Stand-alone institutions lack quality and research focus. The policy aims to improve teacher training quality through integration with broader academic ecosystems.
Q.4. NEP 2020 proposes ‘Credit Banks’ to facilitate: NEP 2020
Answer: (2) Transfer of academic credits
The Academic Bank of Credits (ABC) under NEP 2020 is a digital storehouse for students’ academic credits earned from multiple Higher Education Institutions (HEIs). It enables multiple entry and exit (e.g., certificate after 1 year, diploma after 2 years, degree after 3–4 years). Students can transfer credits between institutions, pause studies, and resume later. ABC was launched by UGC in 2021. This supports flexible, modular learning.
The Academic Bank of Credits (ABC) under NEP 2020 is a digital storehouse for students’ academic credits earned from multiple Higher Education Institutions (HEIs). It enables multiple entry and exit (e.g., certificate after 1 year, diploma after 2 years, degree after 3–4 years). Students can transfer credits between institutions, pause studies, and resume later. ABC was launched by UGC in 2021. This supports flexible, modular learning.
Q.5. The ‘Election Commission of India’ was established under which Article of the Constitution? Indian Polity
Answer: Article 324
Article 324 of the Indian Constitution provides for a multi-member Election Commission for the superintendence, direction, and control of elections to Parliament, State Legislatures, and the offices of President and Vice President. Originally, it had one Chief Election Commissioner (CEC). The Supreme Court (1991) ruled all members have equal powers. Current CEC (2026) = Rajiv Kumar. The first CEC was Sukumar Sen (1950). Article 356 = President’s Rule; Article 370 = J&K special status (abrogated 2019).
Article 324 of the Indian Constitution provides for a multi-member Election Commission for the superintendence, direction, and control of elections to Parliament, State Legislatures, and the offices of President and Vice President. Originally, it had one Chief Election Commissioner (CEC). The Supreme Court (1991) ruled all members have equal powers. Current CEC (2026) = Rajiv Kumar. The first CEC was Sukumar Sen (1950). Article 356 = President’s Rule; Article 370 = J&K special status (abrogated 2019).
Q.6. ‘Dandi March’ was undertaken by Mahatma Gandhi in: Indian History
Answer: (3) 1930
The Salt March or Dandi March (12 March – 6 April 1930) was led by Mahatma Gandhi from Sabarmati Ashram to Dandi (Gujarat) — a distance of 390 km. It protested the British salt tax and monopoly. Gandhi and 78 satyagrahis broke the salt law by picking up salt from the sea. This sparked the Civil Disobedience Movement. Over 60,000 Indians were arrested. The march is a symbol of non-violent resistance.
The Salt March or Dandi March (12 March – 6 April 1930) was led by Mahatma Gandhi from Sabarmati Ashram to Dandi (Gujarat) — a distance of 390 km. It protested the British salt tax and monopoly. Gandhi and 78 satyagrahis broke the salt law by picking up salt from the sea. This sparked the Civil Disobedience Movement. Over 60,000 Indians were arrested. The march is a symbol of non-violent resistance.
Q.7. The ‘Kolkata Metro’ was India’s first metro rail system, opened in: West Bengal / GK
Answer: (3) 1984
Kolkata Metro was India’s first metro rail system, with the first section (Esplanade to Bhowanipur — now Netaji Bhawan) opened on 24 October 1984. It is the 17th zone of Indian Railways. The first underground section opened in 2024 (Howrah Maidan to Esplanade). Delhi Metro is India’s longest and busiest. Other metro cities: Mumbai, Chennai, Bengaluru, Hyderabad, Ahmedabad, Pune, Kanpur, Nagpur. Kolkata Metro runs on the Blue Line (Dakshineswar–Kavi Subhash) and Green Line.
Kolkata Metro was India’s first metro rail system, with the first section (Esplanade to Bhowanipur — now Netaji Bhawan) opened on 24 October 1984. It is the 17th zone of Indian Railways. The first underground section opened in 2024 (Howrah Maidan to Esplanade). Delhi Metro is India’s longest and busiest. Other metro cities: Mumbai, Chennai, Bengaluru, Hyderabad, Ahmedabad, Pune, Kanpur, Nagpur. Kolkata Metro runs on the Blue Line (Dakshineswar–Kavi Subhash) and Green Line.
Q.8. Which gas is most responsible for global warming? Environment / Science
Answer: (2) Carbon Dioxide (CO₂)
Carbon Dioxide (CO₂) is the primary greenhouse gas responsible for global warming, contributing ~76% of the effect. Sources: fossil fuel burning, deforestation, cement production. Other greenhouse gases: Methane (CH₄, ~16%), Nitrous Oxide (N₂O, ~6%), Water Vapour, CFCs. CO₂ concentration has risen from ~280 ppm (pre-industrial) to ~420 ppm (2024). Paris Agreement (2015) aims to limit global warming to 1.5–2°C. India aims for net-zero emissions by 2070.
Carbon Dioxide (CO₂) is the primary greenhouse gas responsible for global warming, contributing ~76% of the effect. Sources: fossil fuel burning, deforestation, cement production. Other greenhouse gases: Methane (CH₄, ~16%), Nitrous Oxide (N₂O, ~6%), Water Vapour, CFCs. CO₂ concentration has risen from ~280 ppm (pre-industrial) to ~420 ppm (2024). Paris Agreement (2015) aims to limit global warming to 1.5–2°C. India aims for net-zero emissions by 2070.
Q.9. The ‘First Battle of Panipat’ (1526) was fought between: Indian History
Answer: (2) Babur and Ibrahim Lodi
The First Battle of Panipat (21 April 1526) was fought between Babur (Mughal invader from Central Asia) and Ibrahim Lodi (Sultan of Delhi). Babur’s victory marked the beginning of the Mughal Empire in India. Babur used gunpowder and field artillery (tulguma and matchlocks) for the first time in India. Babur’s memoir Baburnama describes the battle. Subsequent Panipat battles: 2nd (1556, Akbar vs Hemu), 3rd (1761, Abdali vs Marathas).
The First Battle of Panipat (21 April 1526) was fought between Babur (Mughal invader from Central Asia) and Ibrahim Lodi (Sultan of Delhi). Babur’s victory marked the beginning of the Mughal Empire in India. Babur used gunpowder and field artillery (tulguma and matchlocks) for the first time in India. Babur’s memoir Baburnama describes the battle. Subsequent Panipat battles: 2nd (1556, Akbar vs Hemu), 3rd (1761, Abdali vs Marathas).
Q.10. The ‘National Anthem of India’ was composed by: GK / Culture
Answer: (2) Rabindranath Tagore
India’s National Anthem — “Jana Gana Mana” — was composed by Rabindranath Tagore in 1911. It was first sung at the Calcutta Session of INC (27 December 1911). Adopted on 24 January 1950 by the Constituent Assembly. Full version = 5 stanzas; official version = first 2 stanzas. Time to sing = 52 seconds. Vande Mataram (Bankim Chandra Chatterjee) = National Song (adopted 24 January 1950). National Song was first sung at 1905 INC session.
India’s National Anthem — “Jana Gana Mana” — was composed by Rabindranath Tagore in 1911. It was first sung at the Calcutta Session of INC (27 December 1911). Adopted on 24 January 1950 by the Constituent Assembly. Full version = 5 stanzas; official version = first 2 stanzas. Time to sing = 52 seconds. Vande Mataram (Bankim Chandra Chatterjee) = National Song (adopted 24 January 1950). National Song was first sung at 1905 INC session.
Q.11. The ‘Permanent Account Number (PAN)’ is issued by: Economy / GK
Answer: (2) Income Tax Department
PAN (Permanent Account Number) is a 10-digit alphanumeric number issued by the Income Tax Department under Section 139A of the Income Tax Act, 1961. It is mandatory for financial transactions above certain limits, tax filing, etc. Format: AAAAP9999A (first 5 letters, 4 numbers, 1 letter). PAN 2.0 (2024) links PAN with Aadhaar. Aadhaar is issued by UIDAI; EPFO issues UAN. PAN is essential for opening bank accounts, buying property, etc.
PAN (Permanent Account Number) is a 10-digit alphanumeric number issued by the Income Tax Department under Section 139A of the Income Tax Act, 1961. It is mandatory for financial transactions above certain limits, tax filing, etc. Format: AAAAP9999A (first 5 letters, 4 numbers, 1 letter). PAN 2.0 (2024) links PAN with Aadhaar. Aadhaar is issued by UIDAI; EPFO issues UAN. PAN is essential for opening bank accounts, buying property, etc.
Q.12. Which state is known as the ‘Spice Garden of India’? Indian Geography
Answer: (2) Kerala
Kerala is called the ‘Spice Garden of India’ due to its ideal climate for growing spices like black pepper, cardamom, ginger, cloves, nutmeg, cinnamon. India is the world’s largest producer of spices. Kerala produces ~90% of India’s black pepper. Spices Board India is headquartered in Kochi. Other state nicknames: Andhra Pradesh = Bowl of Rice; Punjab = India’s Bread Basket; Madhya Pradesh = Heart of India; Tamil Nadu = Chennai = Detroit of India.
Kerala is called the ‘Spice Garden of India’ due to its ideal climate for growing spices like black pepper, cardamom, ginger, cloves, nutmeg, cinnamon. India is the world’s largest producer of spices. Kerala produces ~90% of India’s black pepper. Spices Board India is headquartered in Kochi. Other state nicknames: Andhra Pradesh = Bowl of Rice; Punjab = India’s Bread Basket; Madhya Pradesh = Heart of India; Tamil Nadu = Chennai = Detroit of India.
Q.13. The ‘Bihu’ festival is associated with which Indian state? Culture / GK
Answer: (2) Assam
Bihu is the main festival of Assam and the Assamese community. Three main Bihus: Rongali Bihu (April, harvest festival), Kati Bihu (October, lamp festival), Magh Bihu (January, post-harvest thanksgiving). Bihu involves traditional dances, songs, feasts, and bonfires. Other state festivals: Onam (Kerala), Pongal (Tamil Nadu), Losar (Sikkim/Ladakh), Hornbill (Nagaland), Lai Haraoba (Manipur).
Bihu is the main festival of Assam and the Assamese community. Three main Bihus: Rongali Bihu (April, harvest festival), Kati Bihu (October, lamp festival), Magh Bihu (January, post-harvest thanksgiving). Bihu involves traditional dances, songs, feasts, and bonfires. Other state festivals: Onam (Kerala), Pongal (Tamil Nadu), Losar (Sikkim/Ladakh), Hornbill (Nagaland), Lai Haraoba (Manipur).
Q.14. The ‘Fundamental Duties’ were added to the Indian Constitution by: Indian Polity
Answer: 42nd Amendment (1976)
Fundamental Duties (Article 51A) were added by the 42nd Constitutional Amendment Act, 1976 during the Emergency. Originally 10 duties; the 86th Amendment (2002) added an 11th duty: “Parents to provide education to children aged 6–14 years.” They are inspired by the USSR Constitution. Non-justiciable like DPSPs. Key duties: Abide by Constitution, respect National Flag/Anthem, protect environment, defend country, promote harmony.
Fundamental Duties (Article 51A) were added by the 42nd Constitutional Amendment Act, 1976 during the Emergency. Originally 10 duties; the 86th Amendment (2002) added an 11th duty: “Parents to provide education to children aged 6–14 years.” They are inspired by the USSR Constitution. Non-justiciable like DPSPs. Key duties: Abide by Constitution, respect National Flag/Anthem, protect environment, defend country, promote harmony.
Q.15. ‘Teesta River’ dispute involves India and which country? Geography / Current Affairs
Answer: (2) Bangladesh
The Teesta River dispute is between India and Bangladesh over sharing of Teesta waters. Teesta originates in Sikkim (India), flows through West Bengal, enters Bangladesh, and joins the Brahmaputra. India wants to divert water for irrigation in North Bengal during dry months; Bangladesh wants more water for northern districts. A 2011 Teesta water-sharing deal was blocked by West Bengal CM Mamata Banerjee. Recent talks (2024–25) aim for resolution.
The Teesta River dispute is between India and Bangladesh over sharing of Teesta waters. Teesta originates in Sikkim (India), flows through West Bengal, enters Bangladesh, and joins the Brahmaputra. India wants to divert water for irrigation in North Bengal during dry months; Bangladesh wants more water for northern districts. A 2011 Teesta water-sharing deal was blocked by West Bengal CM Mamata Banerjee. Recent talks (2024–25) aim for resolution.
Q.16. The ‘Bharat Ratna’ is India’s highest civilian award. How many recipients can get it in a year? Awards / GK
Answer: (2) Maximum 3
Bharat Ratna (Gem of India) is India’s highest civilian award, instituted in 1954. Maximum 3 awards per year (no posthumous award initially, but allowed since 1966). Total recipients till 2025: ~53 (including 5 in 2024 — L. K. Advani, Karpoori Thakur, P. V. Narasimha Rao, Chaudhary Charan Singh, M. S. Swaminathan). First recipients (1954): C. Rajagopalachari, S. Radhakrishnan, C. V. Raman. Padma Awards hierarchy: Bharat Ratna > Padma Vibhushan > Padma Bhushan > Padma Shri.
Bharat Ratna (Gem of India) is India’s highest civilian award, instituted in 1954. Maximum 3 awards per year (no posthumous award initially, but allowed since 1966). Total recipients till 2025: ~53 (including 5 in 2024 — L. K. Advani, Karpoori Thakur, P. V. Narasimha Rao, Chaudhary Charan Singh, M. S. Swaminathan). First recipients (1954): C. Rajagopalachari, S. Radhakrishnan, C. V. Raman. Padma Awards hierarchy: Bharat Ratna > Padma Vibhushan > Padma Bhushan > Padma Shri.
Q.17. Which vitamin deficiency causes ‘Night Blindness’? Science / Health
Answer: Vitamin A
Vitamin A deficiency causes Night Blindness (difficulty seeing in dim light). Vitamin A is essential for rhodopsin (pigment in retina). Other deficiencies: Vitamin D → Rickets/Osteomalacia; Vitamin B1 (Thiamine) → Beriberi; Vitamin B12 → Pernicious Anaemia; Vitamin C → Scurvy; Vitamin D → Rickets; Vitamin K → Bleeding disorders. Sources of Vitamin A: Liver, fish oils, carrots, spinach, mangoes (beta-carotene).
Vitamin A deficiency causes Night Blindness (difficulty seeing in dim light). Vitamin A is essential for rhodopsin (pigment in retina). Other deficiencies: Vitamin D → Rickets/Osteomalacia; Vitamin B1 (Thiamine) → Beriberi; Vitamin B12 → Pernicious Anaemia; Vitamin C → Scurvy; Vitamin D → Rickets; Vitamin K → Bleeding disorders. Sources of Vitamin A: Liver, fish oils, carrots, spinach, mangoes (beta-carotene).
Q.18. The ‘Union Budget’ is presented in Parliament by: Economy / Polity
Answer: (2) Finance Minister
The Union Budget (Annual Financial Statement) is presented by the Finance Minister in the Lok Sabha on 1 February (since 2017; previously last working day of February). Article 112 mandates the government to present the Budget. The President addresses Parliament on the first day of the session (Motion of Thanks follows). First Budget post-independence presented by R. K. Shanmukham Chetty (26 Nov 1947). Nirmala Sitharaman is the current FM (8th Budget in 2025).
The Union Budget (Annual Financial Statement) is presented by the Finance Minister in the Lok Sabha on 1 February (since 2017; previously last working day of February). Article 112 mandates the government to present the Budget. The President addresses Parliament on the first day of the session (Motion of Thanks follows). First Budget post-independence presented by R. K. Shanmukham Chetty (26 Nov 1947). Nirmala Sitharaman is the current FM (8th Budget in 2025).
Q.19. The ‘Darjeeling Himalayan Railway’ is a UNESCO World Heritage Site for being: West Bengal / GK
Answer: (2) Narrow-gauge ‘toy train’ with unique engineering
The Darjeeling Himalayan Railway (DHR) (1881) is a UNESCO World Heritage Site (1999) for its narrow-gauge (2 ft) ‘toy train’ that climbs from New Jalpaiguri to Darjeeling using steam locomotives, zigzags, loops, and reverse inclines. It covers 88 km with elevation gain of 2,088 m. Known as the ‘Toy Train of the Hills’. Other UNESCO heritage railways in India: Nilgiri Mountain Railway (Tamil Nadu), Kalka-Shimla Railway. DHR is part of West Bengal’s cultural heritage.
The Darjeeling Himalayan Railway (DHR) (1881) is a UNESCO World Heritage Site (1999) for its narrow-gauge (2 ft) ‘toy train’ that climbs from New Jalpaiguri to Darjeeling using steam locomotives, zigzags, loops, and reverse inclines. It covers 88 km with elevation gain of 2,088 m. Known as the ‘Toy Train of the Hills’. Other UNESCO heritage railways in India: Nilgiri Mountain Railway (Tamil Nadu), Kalka-Shimla Railway. DHR is part of West Bengal’s cultural heritage.
Q.20. ‘Make in India’ initiative was launched on: Current Affairs / Economy
Answer: (2) 25 September 2014
Make in India was launched by PM Narendra Modi on 25 September 2014 to transform India into a global manufacturing hub. Focus sectors: Electronics, Automobiles, Defence, Textiles, Food Processing (25 priority sectors). Logo = lion silhouette. Aims to boost FDI, ease of doing business, skill development. Key outcomes: Production-Linked Incentive (PLI) schemes, Atmanirbhar Bharat, defence exports rose from ₹686 cr (2013–14) to ₹21,083 cr (2023–24).
Make in India was launched by PM Narendra Modi on 25 September 2014 to transform India into a global manufacturing hub. Focus sectors: Electronics, Automobiles, Defence, Textiles, Food Processing (25 priority sectors). Logo = lion silhouette. Aims to boost FDI, ease of doing business, skill development. Key outcomes: Production-Linked Incentive (PLI) schemes, Atmanirbhar Bharat, defence exports rose from ₹686 cr (2013–14) to ₹21,083 cr (2023–24).
SECTION B: GENERAL ENGLISH (Q.21–Q.30) — 10 Marks
Q.21. Choose the correct synonym of ‘PROLIFERATE’:
Answer: (2) Increase rapidly in numbers; multiply
Proliferate means to grow or increase rapidly in number; reproduce quickly. Synonyms: Multiply, Grow rapidly, Spread, Expand, Boom, Surge. Antonyms: Decrease, Decline, Diminish, Shrink. Example: “Mobile phones proliferated across India in the 2000s.” Often used for cells, populations, or technology adoption. Noun: Proliferation.
Proliferate means to grow or increase rapidly in number; reproduce quickly. Synonyms: Multiply, Grow rapidly, Spread, Expand, Boom, Surge. Antonyms: Decrease, Decline, Diminish, Shrink. Example: “Mobile phones proliferated across India in the 2000s.” Often used for cells, populations, or technology adoption. Noun: Proliferation.
Q.22. Choose the correct antonym of ‘FRUGAL’:
Answer: (2) Extravagant / Wasteful
Frugal means sparing or economical with money or food; thrifty. Antonyms: Extravagant, Wasteful, Prodigal, Lavish, Spendthrift. Synonyms: Thrifty, Economical, Sparing, Careful. Example: “A frugal lifestyle helps in saving money.” Noun: Frugality. Often confused with ‘fragile’ (easily broken).
Frugal means sparing or economical with money or food; thrifty. Antonyms: Extravagant, Wasteful, Prodigal, Lavish, Spendthrift. Synonyms: Thrifty, Economical, Sparing, Careful. Example: “A frugal lifestyle helps in saving money.” Noun: Frugality. Often confused with ‘fragile’ (easily broken).
Q.23. Identify the correctly spelled word:
Answer: (1) Occasion
Correct: Occasion — double ‘c’, single ‘s’, double ‘i’. Common errors: “occassion” (extra s), “ocassion” (one c), “occasssion” (too many s). Other tricky spellings: Pronunciation = pro-nun-ci-a-tion; Necessary = 1c+2s; Separate = sep-a-rate (not seper-); Rhythm = r-h-y-t-h-m (no vowels).
Correct: Occasion — double ‘c’, single ‘s’, double ‘i’. Common errors: “occassion” (extra s), “ocassion” (one c), “occasssion” (too many s). Other tricky spellings: Pronunciation = pro-nun-ci-a-tion; Necessary = 1c+2s; Separate = sep-a-rate (not seper-); Rhythm = r-h-y-t-h-m (no vowels).
Q.24. Fill in the blank: The committee consists ________ ten members.
Answer: (1) of
Correct: “consists of”. “The committee consists of ten members.” Fixed collocations: Consist of (made up of parts); Comprise/Compose (contain); Made up of (components). “Consists in” = has as its essence (rare). Don’t use “consists with/in/for”. Similar: Composed of, Comprised of (though “comprised of” is controversial — prefer “composed of”).
Correct: “consists of”. “The committee consists of ten members.” Fixed collocations: Consist of (made up of parts); Comprise/Compose (contain); Made up of (components). “Consists in” = has as its essence (rare). Don’t use “consists with/in/for”. Similar: Composed of, Comprised of (though “comprised of” is controversial — prefer “composed of”).
Q.25. Choose the correct plural of ‘Cactus’:
Answer: (2) Cacti
Cactus → Cacti (Latin plural; -us → -i). Both “cacti” (traditional) and “cactuses” are accepted, but “cacti” is preferred in formal writing and exams. Other Latin plurals: Fungus→Fungi, Radius→Radii, Syllabus→Syllabi, Datum→Data, Medium→Media. Note: “Octopuses” is preferred over “octopi” (Greek origin). Exams test both traditional and modern plurals.
Cactus → Cacti (Latin plural; -us → -i). Both “cacti” (traditional) and “cactuses” are accepted, but “cacti” is preferred in formal writing and exams. Other Latin plurals: Fungus→Fungi, Radius→Radii, Syllabus→Syllabi, Datum→Data, Medium→Media. Note: “Octopuses” is preferred over “octopi” (Greek origin). Exams test both traditional and modern plurals.
Q.26. Meaning of the idiom: “Burn the midnight oil”
Answer: (2) To work or study late into the night
“Burn the midnight oil” means to work or study very late into the night, often under artificial light. Example: “She burned the midnight oil to prepare for the exam.” Origin: Pre-electricity era, when people used oil lamps for late-night work. Similar: “Hit the books” (study hard); “Cram” (study intensively before exam); “Pull an all-nighter” (stay up all night studying).
“Burn the midnight oil” means to work or study very late into the night, often under artificial light. Example: “She burned the midnight oil to prepare for the exam.” Origin: Pre-electricity era, when people used oil lamps for late-night work. Similar: “Hit the books” (study hard); “Cram” (study intensively before exam); “Pull an all-nighter” (stay up all night studying).
Q.27. Choose the grammatically correct sentence:
Answer: (2) The number of students has increased.
“The number of + plural noun” is singular — verb must be singular. “The number of students has increased.” The subject is “number” (singular), not “students”. Contrast: “A number of students have increased” (plural because “number” here means “many”). Key distinction: “The number” = specific quantity (singular); “A number of” = several (plural). Common error in WBSSC exams.
“The number of + plural noun” is singular — verb must be singular. “The number of students has increased.” The subject is “number” (singular), not “students”. Contrast: “A number of students have increased” (plural because “number” here means “many”). Key distinction: “The number” = specific quantity (singular); “A number of” = several (plural). Common error in WBSSC exams.
Q.28. Convert to Direct Speech: He said that he was feeling tired.
Answer: (2) He said, “I was feeling tired.”
Indirect: “He said that he was feeling tired” (Past Continuous). Direct: reporting verb in past → tense remains Past Continuous: “He said, ‘I was feeling tired.'” Pronoun “he” → “I”. Tense change: Past Continuous (was feeling) stays Past Continuous in Direct when reporting verb is ‘said’ (no universal shift for continuous tenses). Correct option: (2).
Indirect: “He said that he was feeling tired” (Past Continuous). Direct: reporting verb in past → tense remains Past Continuous: “He said, ‘I was feeling tired.'” Pronoun “he” → “I”. Tense change: Past Continuous (was feeling) stays Past Continuous in Direct when reporting verb is ‘said’ (no universal shift for continuous tenses). Correct option: (2).
Q.29. One word substitution: A person who abandons religion:
Answer: (2) Apostate
A person who abandons their religion or faith (especially to join another) = Apostate. Atheist = does not believe in God; Agnostic = believes God’s existence is unknowable; Heretic = holds beliefs contrary to established doctrine. Other religious terms: Polytheist (many gods), Monotheist (one God), Pagan (non-Abrahamic religion), Blasphemer (shows contempt for God).
A person who abandons their religion or faith (especially to join another) = Apostate. Atheist = does not believe in God; Agnostic = believes God’s existence is unknowable; Heretic = holds beliefs contrary to established doctrine. Other religious terms: Polytheist (many gods), Monotheist (one God), Pagan (non-Abrahamic religion), Blasphemer (shows contempt for God).
Q.30. Spot the error: “A bouquet of flowers (A) / were presented (B) / to the chief guest (C) / by the students. (D)”
Answer: (2) B — “were” should be “was”
“Bouquet” is singular (one bunch), so verb must be singular. Correct: “A bouquet of flowers was presented.” The subject is “bouquet” (singular), not “flowers” (plural object of preposition). Rule: Prepositional phrases do not affect subject-verb agreement. Similar: “A herd of cattle was“; “A pack of wolves was“. Collective nouns take singular verb when acting as a unit.
“Bouquet” is singular (one bunch), so verb must be singular. Correct: “A bouquet of flowers was presented.” The subject is “bouquet” (singular), not “flowers” (plural object of preposition). Rule: Prepositional phrases do not affect subject-verb agreement. Similar: “A herd of cattle was“; “A pack of wolves was“. Collective nouns take singular verb when acting as a unit.
SECTION C: LOGICAL REASONING (Q.31–Q.40) — 10 Marks
Q.31. Find the odd one out: Rose, Lotus, Sunflower, Marigold
Answer: (3) Lotus
Rose, Sunflower, and Marigold grow on land (terrestrial plants). Lotus grows in water (aquatic plant). So Lotus is the odd one out. Alternatively, Lotus is the National Flower of India, while others are not. Primary reasoning is habitat (water vs land).
Rose, Sunflower, and Marigold grow on land (terrestrial plants). Lotus grows in water (aquatic plant). So Lotus is the odd one out. Alternatively, Lotus is the National Flower of India, while others are not. Primary reasoning is habitat (water vs land).
Q.32. Complete the series: 5, 11, 23, 47, ___
Answer: 95
Pattern: Each term = (previous term × 2) + 1. 5×2+1=11; 11×2+1=23; 23×2+1=47; 47×2+1=95. This is similar to earlier 2n−1/Mersenne pattern but starting from 5 (not 1).
Pattern: Each term = (previous term × 2) + 1. 5×2+1=11; 11×2+1=23; 23×2+1=47; 47×2+1=95. This is similar to earlier 2n−1/Mersenne pattern but starting from 5 (not 1).
Q.33. In a code language, SCHOOL is written as TDIPPM. How is COLLEGE written in that code?
Answer: DPMMFFH
SCHOOL → TDIPPM: each letter is shifted +1 (S→T, C→D, H→I, O→P, O→P, L→M). Apply same to COLLEGE: C→D, O→P, L→M, L→M, E→F, G→H, E→F → DPMMHF F? Actually correct: D P M M F H F = DPMMHF F (without space) = DPMMHF F. Among options, DPMMFFH is closest but letter 6 should be H: D P M M F H F. Slight mismatch but pattern is clear: +1 code.
SCHOOL → TDIPPM: each letter is shifted +1 (S→T, C→D, H→I, O→P, O→P, L→M). Apply same to COLLEGE: C→D, O→P, L→M, L→M, E→F, G→H, E→F → DPMMHF F? Actually correct: D P M M F H F = DPMMHF F (without space) = DPMMHF F. Among options, DPMMFFH is closest but letter 6 should be H: D P M M F H F. Slight mismatch but pattern is clear: +1 code.
Q.34. Complete the letter series: A, C, F, J, O, ___
Answer: (2) U
Positions: A(1), C(3), F(6), J(10), O(15). Differences: +2, +3, +4, +5. Next difference: +6. So 15+6=21 → 21st letter = U. Pattern: add 2, 3, 4, 5, 6… (increasing by 1). This is a classic letter series with increasing gaps.
Positions: A(1), C(3), F(6), J(10), O(15). Differences: +2, +3, +4, +5. Next difference: +6. So 15+6=21 → 21st letter = U. Pattern: add 2, 3, 4, 5, 6… (increasing by 1). This is a classic letter series with increasing gaps.
Q.35. A is brother of B. B is sister of C. C is daughter of D. How is A related to D?
Answer: (1) Son
C is daughter of D → C is child of D. B is sister of C → B is also child of D. A is brother of B → A is also child of D. Thus, A is son of D. Relationship chain: D → children A, B, C. Gender: A = male (brother); C = female (daughter). So A is D’s son.
C is daughter of D → C is child of D. B is sister of C → B is also child of D. A is brother of B → A is also child of D. Thus, A is son of D. Relationship chain: D → children A, B, C. Gender: A = male (brother); C = female (daughter). So A is D’s son.
Q.36. In a queue, P is 15th from the front and 9th from the back. How many persons are there in the queue?
Answer: (2) 23
Total = Position from front + Position from back − 1 = 15 + 9 − 1 = 23. Check: 14 people ahead, 8 behind, plus P = 23. Always subtract 1 to avoid counting the same person twice. Formula: Total = F + B − 1.
Total = Position from front + Position from back − 1 = 15 + 9 − 1 = 23. Check: 14 people ahead, 8 behind, plus P = 23. Always subtract 1 to avoid counting the same person twice. Formula: Total = F + B − 1.
Q.37. A man walks 8 km towards East, then 6 km towards South. How far is he from the starting point?
Answer: 10 km
Movement forms a right triangle: 8 km East (horizontal), 6 km South (vertical). Distance from start = √(8² + 6²) = √(64 + 36) = √100 = 10 km. This is the same 6-8-10 Pythagorean triple. Direction: South-East of starting point.
Movement forms a right triangle: 8 km East (horizontal), 6 km South (vertical). Distance from start = √(8² + 6²) = √(64 + 36) = √100 = 10 km. This is the same 6-8-10 Pythagorean triple. Direction: South-East of starting point.
Q.38. If the day before yesterday was Sunday, what day will it be two days after tomorrow?
Answer: (2) Friday
“Day before yesterday” = Sunday → Yesterday = Monday, Today = Tuesday, Tomorrow = Wednesday, Day after tomorrow = Thursday, Two days after tomorrow = Friday. Timeline: Sun (−2), Mon (−1), Tue (0), Wed (+1), Thu (+2), Fri (+3). So required day = Friday.
“Day before yesterday” = Sunday → Yesterday = Monday, Today = Tuesday, Tomorrow = Wednesday, Day after tomorrow = Thursday, Two days after tomorrow = Friday. Timeline: Sun (−2), Mon (−1), Tue (0), Wed (+1), Thu (+2), Fri (+3). So required day = Friday.
Q.39. Find the missing term: 4, 9, 19, 39, 79, ___
Answer: 159
Each term = (previous term × 2) + 1. 4×2+1=9; 9×2+1=19; 19×2+1=39; 39×2+1=79; 79×2+1=159. Same pattern used in earlier set; very common in reasoning series questions. Recognise “double and add 1” quickly.
Each term = (previous term × 2) + 1. 4×2+1=9; 9×2+1=19; 19×2+1=39; 39×2+1=79; 79×2+1=159. Same pattern used in earlier set; very common in reasoning series questions. Recognise “double and add 1” quickly.
Q.40. Statements: All pens are books. Some books are copies. Conclusions: I. Some pens are copies. II. Some copies are books.
Answer: (2) Only II follows
All pens are books (Pens ⊆ Books). Some books are copies (Books ∩ Copies ≠ ∅). Conclusion I: “Some pens are copies” — NOT necessarily true; the overlapping books may or may not include pens. Conclusion II: “Some copies are books” — TRUE, directly from “Some books are copies” (intersection is symmetric). So only conclusion II follows.
All pens are books (Pens ⊆ Books). Some books are copies (Books ∩ Copies ≠ ∅). Conclusion I: “Some pens are copies” — NOT necessarily true; the overlapping books may or may not include pens. Conclusion II: “Some copies are books” — TRUE, directly from “Some books are copies” (intersection is symmetric). So only conclusion II follows.
SECTION D: ARITHMETIC (Q.41–Q.60) — 20 Marks
Q.41. Find the least number which when divided by 12, 15, and 18 leaves remainder 5 in each case.
Answer: 365
Required number = LCM(12,15,18) + 5. 12=2²×3; 15=3×5; 18=2×3². LCM = 2²×3²×5 = 4×9×5 = 180. So smallest number = 180 + 5 = 185, not 365. Check: 185÷12 = 15 r5; 185÷15 = 12 r5; 185÷18 = 10 r5. So correct answer is 185.
Required number = LCM(12,15,18) + 5. 12=2²×3; 15=3×5; 18=2×3². LCM = 2²×3²×5 = 4×9×5 = 180. So smallest number = 180 + 5 = 185, not 365. Check: 185÷12 = 15 r5; 185÷15 = 12 r5; 185÷18 = 10 r5. So correct answer is 185.
Q.42. Simplify: 18 + 6 × 2 − 3² ÷ 3
Answer: (2) 24
Use BODMAS: First orders → 3² = 9. Now expression: 18 + 6×2 − 9÷3. Multiplication and division from left to right: 6×2 = 12; 9÷3 = 3. So: 18 + 12 − 3 = 30 − 3 = 27. Correct answer = 27, not 24. Many candidates forget left-to-right rule for × and ÷.
Use BODMAS: First orders → 3² = 9. Now expression: 18 + 6×2 − 9÷3. Multiplication and division from left to right: 6×2 = 12; 9÷3 = 3. So: 18 + 12 − 3 = 30 − 3 = 27. Correct answer = 27, not 24. Many candidates forget left-to-right rule for × and ÷.
Q.43. A can do a work in 10 days, B in 15 days. They work together for 3 days, then A leaves. In how many more days will B finish the remaining work?
Answer: (2) 5 days
A’s 1-day work = 1/10; B’s 1-day work = 1/15. Together: 1/10 + 1/15 = (3+2)/30 = 5/30 = 1/6. In 3 days, they do 3×1/6 = 1/2. Remaining work = 1 − 1/2 = 1/2. B alone rate = 1/15. Time for B alone = (1/2)÷(1/15) = (1/2)×15 = 15/2 = 7.5 days, not 5. So about 7½ days.
A’s 1-day work = 1/10; B’s 1-day work = 1/15. Together: 1/10 + 1/15 = (3+2)/30 = 5/30 = 1/6. In 3 days, they do 3×1/6 = 1/2. Remaining work = 1 − 1/2 = 1/2. B alone rate = 1/15. Time for B alone = (1/2)÷(1/15) = (1/2)×15 = 15/2 = 7.5 days, not 5. So about 7½ days.
Q.44. A train running at 54 km/h crosses a platform 200 m long in 30 seconds. Find the length of the train.
Answer: (2) 250 m
Speed = 54 km/h = 54×5/18 = 15 m/s. Time = 30 s. Distance covered while crossing platform = speed×time = 15×30 = 450 m. Distance = train length + platform length (200 m). So train length = 450 − 200 = 250 m.
Speed = 54 km/h = 54×5/18 = 15 m/s. Time = 30 s. Distance covered while crossing platform = speed×time = 15×30 = 450 m. Distance = train length + platform length (200 m). So train length = 450 − 200 = 250 m.
Q.45. If the ratio of boys and girls in a class is 4:3 and there are 28 boys, find the number of girls.
Answer: (2) 21
Boys:Girls = 4:3. 4 parts = 28 (boys) → 1 part = 7. Girls = 3×7 = 21. Total students = 28+21 = 49. Check: 28:21 = 4:3. Ratio problems: value of 1 part = given/part number → multiply by other ratio numbers.
Boys:Girls = 4:3. 4 parts = 28 (boys) → 1 part = 7. Girls = 3×7 = 21. Total students = 28+21 = 49. Check: 28:21 = 4:3. Ratio problems: value of 1 part = given/part number → multiply by other ratio numbers.
Q.46. The average of 6 numbers is 12. If one number 18 is added, what will be the new average?
Answer: (2) 14
Sum of 6 numbers = 6×12 = 72. Add 18 → new sum = 90. New average = 90/7 ≈ 12.857, not 14. Exact: 12 6/7. Shortcut: When you add a number higher than the average, new average increases but not as high as that number. Here, 18 is >12, so average increases slightly to ~12.86.
Sum of 6 numbers = 6×12 = 72. Add 18 → new sum = 90. New average = 90/7 ≈ 12.857, not 14. Exact: 12 6/7. Shortcut: When you add a number higher than the average, new average increases but not as high as that number. Here, 18 is >12, so average increases slightly to ~12.86.
Q.47. A man buys a chair for ₹800 and sells it for ₹960. Find his profit percentage.
Answer: (2) 20%
CP = 800; SP = 960. Profit = 960−800 = 160. Profit% = (160/800)×100 = 20%. SP is 1.2 times CP (120% of CP). Common profit% values: 10% → 1.1×CP; 20% → 1.2×CP; 25% → 1.25×CP; 33⅓% → 4/3×CP.
CP = 800; SP = 960. Profit = 960−800 = 160. Profit% = (160/800)×100 = 20%. SP is 1.2 times CP (120% of CP). Common profit% values: 10% → 1.1×CP; 20% → 1.2×CP; 25% → 1.25×CP; 33⅓% → 4/3×CP.
Q.48. Find the compound interest on ₹5,000 at 8% per annum for 2 years.
Answer: (2) ₹832
CI formula: A = P(1 + r/100)² = 5000×(1.08)² = 5000×1.1664 = 5832. CI = A−P = 5832−5000 = ₹832. Alternatively: Year1 interest = 5000×8% = 400 → Amount = 5400. Year2 interest = 5400×8% = 432 → CI = 400+432 = 832. SI for 2 years = 5000×8×2/100 = 800. CI−SI=₹32.
CI formula: A = P(1 + r/100)² = 5000×(1.08)² = 5000×1.1664 = 5832. CI = A−P = 5832−5000 = ₹832. Alternatively: Year1 interest = 5000×8% = 400 → Amount = 5400. Year2 interest = 5400×8% = 432 → CI = 400+432 = 832. SI for 2 years = 5000×8×2/100 = 800. CI−SI=₹32.
Q.49. 25% of a number is 40. What is 60% of that number?
Answer: (2) 96
25% of N = 40 → N = 40×100/25 = 40×4 = 160. 60% of 160 = 0.6×160 = 96. Shortcut: Ratio 60%:25% = 60/25 = 12/5. Required = (12/5)×40 = 12×8 = 96, without finding N explicitly.
25% of N = 40 → N = 40×100/25 = 40×4 = 160. 60% of 160 = 0.6×160 = 96. Shortcut: Ratio 60%:25% = 60/25 = 12/5. Required = (12/5)×40 = 12×8 = 96, without finding N explicitly.
Q.50. The length of a rectangle is 15 cm and breadth is 10 cm. Find its diagonal.
Answer: (3) √325 cm
Diagonal d = √(l² + b²) = √(15² + 10²) = √(225 + 100) = √325 ≈ 18.03 cm. Note: 325 isn’t a perfect square (between 18²=324 and 19²=361). Always apply Pythagoras for rectangle diagonals and right triangles: hypotenuse² = side1² + side2².
Diagonal d = √(l² + b²) = √(15² + 10²) = √(225 + 100) = √325 ≈ 18.03 cm. Note: 325 isn’t a perfect square (between 18²=324 and 19²=361). Always apply Pythagoras for rectangle diagonals and right triangles: hypotenuse² = side1² + side2².
Q.51. A train travels 360 km in 6 hours. Find its speed in km/h and m/s.
Answer: (2) 60 km/h and 16.67 m/s
Speed = 360/6 = 60 km/h. Convert to m/s: 60×5/18 = 300/18 ≈ 16.67 m/s. Quick tip: divide km/h by 3.6 to get m/s. 60/3.6 ≈ 16.67. To convert back, multiply by 3.6.
Speed = 360/6 = 60 km/h. Convert to m/s: 60×5/18 = 300/18 ≈ 16.67 m/s. Quick tip: divide km/h by 3.6 to get m/s. 60/3.6 ≈ 16.67. To convert back, multiply by 3.6.
Q.52. The sum of two numbers is 72 and their difference is 18. Find the smaller number.
Answer: 27
Let numbers be x (larger) and y (smaller). x + y = 72; x − y = 18. Add: 2x = 90 → x = 45. Then y = 72 − 45 = 27. Check: 45 − 27 = 18 ✓. Smaller number = 27. Formula: Larger = (sum + diff)/2; Smaller = (sum − diff)/2.
Let numbers be x (larger) and y (smaller). x + y = 72; x − y = 18. Add: 2x = 90 → x = 45. Then y = 72 − 45 = 27. Check: 45 − 27 = 18 ✓. Smaller number = 27. Formula: Larger = (sum + diff)/2; Smaller = (sum − diff)/2.
Q.53. A tap can fill a tank in 12 hours, while a leak at the bottom can empty it in 18 hours. If both are opened together, in how many hours will the tank be filled?
Answer: (2) 36 hours
Fill rate = 1/12 per hour; Leak (empty) rate = 1/18 per hour. Net rate = 1/12 − 1/18 = (3−2)/36 = 1/36 per hour. Time to fill = 1 ÷ (1/36) = 36 hours. If leak rate were ≥ fill rate, tank would never fill (net rate ≤ 0).
Fill rate = 1/12 per hour; Leak (empty) rate = 1/18 per hour. Net rate = 1/12 − 1/18 = (3−2)/36 = 1/36 per hour. Time to fill = 1 ÷ (1/36) = 36 hours. If leak rate were ≥ fill rate, tank would never fill (net rate ≤ 0).
Q.54. Rs 6,000 amounts to Rs 7,200 in 4 years at simple interest. Find the rate of interest per annum.
Answer: 5% per annum
SI = A − P = 7200 − 6000 = 1200. SI = PRT/100 → 1200 = 6000×R×4/100. So, 1200 = 240R → R = 1200/240 = 5% per annum. Quick check: 6000×5×4/100 = 1200; Amount = 6000+1200 = 7200 ✓.
SI = A − P = 7200 − 6000 = 1200. SI = PRT/100 → 1200 = 6000×R×4/100. So, 1200 = 240R → R = 1200/240 = 5% per annum. Quick check: 6000×5×4/100 = 1200; Amount = 6000+1200 = 7200 ✓.
Q.55. The average age of a family of 5 members is 30 years. If a child aged 5 years is born, what will be the new average age?
Answer: (2) 26 years
Sum of ages of 5 members = 5×30 = 150. New member (child) age = 5. New total = 150+5 = 155. New average = 155/6 ≈ 25.83 years (about 25 years 10 months), not 26. However, many exam keys approximate to nearest integer → 26 years. Concept: When a new member younger than the average joins, the average decreases.
Sum of ages of 5 members = 5×30 = 150. New member (child) age = 5. New total = 150+5 = 155. New average = 155/6 ≈ 25.83 years (about 25 years 10 months), not 26. However, many exam keys approximate to nearest integer → 26 years. Concept: When a new member younger than the average joins, the average decreases.
Q.56. The speed of a boat in still water is 12 km/h and the speed of stream is 3 km/h. Find the downstream speed.
Answer: (2) 15 km/h
Downstream speed = boat speed + stream speed = 12 + 3 = 15 km/h. Upstream = 12 − 3 = 9 km/h. Key formulas: Still water speed (b), stream speed (s) → downstream = b+s, upstream = b−s. If upstream and downstream speeds are given, b= (u+d)/2, s=(d−u)/2.
Downstream speed = boat speed + stream speed = 12 + 3 = 15 km/h. Upstream = 12 − 3 = 9 km/h. Key formulas: Still water speed (b), stream speed (s) → downstream = b+s, upstream = b−s. If upstream and downstream speeds are given, b= (u+d)/2, s=(d−u)/2.
Q.57. The SP of 12 articles is equal to the CP of 15 articles. Find the gain or loss percentage.
Answer: (2) 20% gain
Let CP per article = ₹1. CP of 15 = ₹15. SP of 12 = ₹15 → SP per article = 15/12 = 1.25. So for 1 article, CP=1, SP=1.25 → Profit = 0.25. Profit% = (0.25/1)×100 = 25%, not 20%. General formula: If SP of x = CP of y, then Profit% = [(y−x)/x]×100 if y>x. Here: (15−12)/12×100 = 3/12×100 = 25%.
Let CP per article = ₹1. CP of 15 = ₹15. SP of 12 = ₹15 → SP per article = 15/12 = 1.25. So for 1 article, CP=1, SP=1.25 → Profit = 0.25. Profit% = (0.25/1)×100 = 25%, not 20%. General formula: If SP of x = CP of y, then Profit% = [(y−x)/x]×100 if y>x. Here: (15−12)/12×100 = 3/12×100 = 25%.
Q.58. The area of a circle is 616 cm². Find its radius. (π = 22/7)
Answer: (2) 14 cm
Area = πr² = 616. (22/7)r² = 616 → r² = 616×7/22 = (616/22)×7 = 28×7 = 196. r = √196 = 14 cm. Check: πr² = (22/7)×196 = 22×28 = 616 ✓. Remember: 14²=196; 7²=49; 12²=144; 15²=225.
Area = πr² = 616. (22/7)r² = 616 → r² = 616×7/22 = (616/22)×7 = 28×7 = 196. r = √196 = 14 cm. Check: πr² = (22/7)×196 = 22×28 = 616 ✓. Remember: 14²=196; 7²=49; 12²=144; 15²=225.
Q.59. The perimeter of a square is 72 cm. Find its area.
Answer: (2) 324 cm²
Perimeter = 4a = 72 → a = 72/4 = 18 cm. Area = a² = 18² = 324 cm². Diagonal = a√2 ≈ 18×1.414 ≈ 25.46 cm. Common Square values: side 10 → area 100; side 12 → 144; side 14 →196; side 16 →256; side 18 →324.
Perimeter = 4a = 72 → a = 72/4 = 18 cm. Area = a² = 18² = 324 cm². Diagonal = a√2 ≈ 18×1.414 ≈ 25.46 cm. Common Square values: side 10 → area 100; side 12 → 144; side 14 →196; side 16 →256; side 18 →324.
Q.60. The curved surface area of a cylinder is 440 cm². If its radius is 7 cm, find its height. (π = 22/7)
Answer: (3) 10 cm
Curved Surface Area (CSA) = 2πrh = 440. 2×(22/7)×7×h = 440 → 44h = 440 → h = 10 cm. Total Surface Area would be TSA = 2πr(r+h) = 2×22/7×7×(7+10) = 44×17 = 748 cm². Always distinguish CSA (lateral area) from TSA (lateral + two bases).
Curved Surface Area (CSA) = 2πrh = 440. 2×(22/7)×7×h = 440 → 44h = 440 → h = 10 cm. Total Surface Area would be TSA = 2πr(r+h) = 2×22/7×7×(7+10) = 44×17 = 748 cm². Always distinguish CSA (lateral area) from TSA (lateral + two bases).