📋 MOCK TEST – SET 32 🔥
WBSSC Group C (Clerk) — Advanced Level
Total: 60 Questions | GA: 20 | English: 10 | Reasoning: 10 | Arithmetic: 20 | Click option to check answer
SECTION A: GENERAL AWARENESS (Q.1–Q.20) — 20 Marks
Q.1. Under NEP 2020, the proposed ‘National Curriculum Framework for School Education (NCF-SE 2023)’ is based on how many foundational principles? NEP 2020HARD
Answer: (2) 5
NCF-SE 2023 is structured around 5 foundational principles: (1) Rooting education in Indian ethos, (2) Holistic development, (3) Flexibility and choice, (4) Eliminating harmful hierarchies, and (5) Emphasis on competencies over content. It covers all stages: Foundational, Preparatory, Middle, and Secondary. It replaces NCF 2005.
NCF-SE 2023 is structured around 5 foundational principles: (1) Rooting education in Indian ethos, (2) Holistic development, (3) Flexibility and choice, (4) Eliminating harmful hierarchies, and (5) Emphasis on competencies over content. It covers all stages: Foundational, Preparatory, Middle, and Secondary. It replaces NCF 2005.
Q.2. NEP 2020 recommends that by 2030, the minimum degree qualification for teaching at all levels should be: NEP 2020HARD
Answer: (2) 4-year integrated B.Ed.
NEP 2020 mandates that by 2030, the minimum qualification for teaching at any level will be a 4-year integrated B.Ed. programme. This programme integrates subject knowledge + pedagogy + practice. NCTE introduced the 4-year ITEP (Integrated Teacher Education Programme) from 2023–24 in select universities. Replaces standalone 2-year B.Ed.
NEP 2020 mandates that by 2030, the minimum qualification for teaching at any level will be a 4-year integrated B.Ed. programme. This programme integrates subject knowledge + pedagogy + practice. NCTE introduced the 4-year ITEP (Integrated Teacher Education Programme) from 2023–24 in select universities. Replaces standalone 2-year B.Ed.
Q.3. Under NEP 2020, ‘Balvatikas’ are: NEP 2020HARD
Answer: (2) Pre-primary classes attached to primary schools
Balvatikas are pre-primary classes for children aged 3–6 years to be attached to existing Govt. primary/upper primary schools. Part of NEP 2020’s Foundational Stage (5+3+3+4 structure). KV schools have started Balvatikas from 2022. Aim: universal access to quality early childhood education under the school system.
Balvatikas are pre-primary classes for children aged 3–6 years to be attached to existing Govt. primary/upper primary schools. Part of NEP 2020’s Foundational Stage (5+3+3+4 structure). KV schools have started Balvatikas from 2022. Aim: universal access to quality early childhood education under the school system.
Q.4. The NEP 2020 document was released in July 2020 under which Union Minister of Education? NEP 2020HARD
Answer: (2) Ramesh Pokhriyal ‘Nishank’
NEP 2020 was officially released on 29 July 2020 under the Union Minister of Education Ramesh Pokhriyal ‘Nishank’. The policy was drafted by the K. Kasturirangan Committee. It replaced the National Policy on Education 1986 (modified 1992). Dharmendra Pradhan became Education Minister in July 2021.
NEP 2020 was officially released on 29 July 2020 under the Union Minister of Education Ramesh Pokhriyal ‘Nishank’. The policy was drafted by the K. Kasturirangan Committee. It replaced the National Policy on Education 1986 (modified 1992). Dharmendra Pradhan became Education Minister in July 2021.
Q.5. ‘Operation Polo’ (1948) refers to: Indian HistoryHARD
Answer: (2) Integration of Hyderabad
Operation Polo (September 1948): Indian military (“Police Action”) under Major General J.N. Chaudhuri to integrate the Hyderabad State (Nizam Osman Ali Khan) into India. Lasted 5 days. Hyderabad was the largest princely state. Operation Vijay (1961) = Goa liberation.
Operation Polo (September 1948): Indian military (“Police Action”) under Major General J.N. Chaudhuri to integrate the Hyderabad State (Nizam Osman Ali Khan) into India. Lasted 5 days. Hyderabad was the largest princely state. Operation Vijay (1961) = Goa liberation.
Q.6. The ‘Vernacular Press Act’ (1878) was repealed by: Indian HistoryHARD
Answer: (2) Lord Ripon
Vernacular Press Act (1878) passed by Lord Lytton to muzzle Indian-language newspapers (called “Gagging Act”). Repealed in 1882 by Lord Ripon (known for liberal policies and local self-government). Ripon is also known for Ilbert Bill controversy and First Factory Act (1881).
Vernacular Press Act (1878) passed by Lord Lytton to muzzle Indian-language newspapers (called “Gagging Act”). Repealed in 1882 by Lord Ripon (known for liberal policies and local self-government). Ripon is also known for Ilbert Bill controversy and First Factory Act (1881).
Q.7. The ‘Damodar Valley Corporation (DVC)’ was established in: West BengalHARD
Answer: (2) 1948
Damodar Valley Corporation (DVC) established by DVC Act, 1948 — India’s first multipurpose river valley project, modelled on Tennessee Valley Authority (USA). Covers Damodar River basin across West Bengal and Jharkhand. Provides flood control, irrigation, power, and navigation. Headquarters: Kolkata.
Damodar Valley Corporation (DVC) established by DVC Act, 1948 — India’s first multipurpose river valley project, modelled on Tennessee Valley Authority (USA). Covers Damodar River basin across West Bengal and Jharkhand. Provides flood control, irrigation, power, and navigation. Headquarters: Kolkata.
Q.8. ‘Photoelectric effect’ — for which Einstein received the Nobel Prize (1921) — states that: ScienceHARD
Answer: (2) Electrons emitted when light of sufficient frequency hits metal
Photoelectric effect: when light of frequency above a threshold hits a metal surface, electrons (photoelectrons) are emitted. Einstein explained it using the photon concept. KE of electron = hf − φ (work function). Nobel Prize 1921. Forms basis of solar cells.
Photoelectric effect: when light of frequency above a threshold hits a metal surface, electrons (photoelectrons) are emitted. Einstein explained it using the photon concept. KE of electron = hf − φ (work function). Nobel Prize 1921. Forms basis of solar cells.
Q.9. The ‘Poona Pact’ (1932) was signed between: Indian HistoryHARD
Answer: (2) Gandhi and B.R. Ambedkar
Poona Pact (September 1932): signed between Gandhi and B.R. Ambedkar after Gandhi’s fast-unto-death in Yeravda Jail. Replaced the Communal Award (separate electorates for Depressed Classes) with reserved seats within joint Hindu electorate. 148 seats reserved in provincial legislatures.
Poona Pact (September 1932): signed between Gandhi and B.R. Ambedkar after Gandhi’s fast-unto-death in Yeravda Jail. Replaced the Communal Award (separate electorates for Depressed Classes) with reserved seats within joint Hindu electorate. 148 seats reserved in provincial legislatures.
Q.10. The ‘One Nation One Ration Card (ONORC)’ scheme allows: Current AffairsHARD
Answer: (2) Migrants to access PDS from any FPS via biometric
ONORC launched 2019 under NFSA. Allows migrant NFSA beneficiaries to lift their entitled food grains from any Fair Price Shop anywhere in India using Aadhaar-based biometric authentication via PoS machine. Implemented in all 36 States/UTs. Over 100 crore portability transactions recorded.
ONORC launched 2019 under NFSA. Allows migrant NFSA beneficiaries to lift their entitled food grains from any Fair Price Shop anywhere in India using Aadhaar-based biometric authentication via PoS machine. Implemented in all 36 States/UTs. Over 100 crore portability transactions recorded.
Q.11. Which Constitutional Amendment added the words ‘Socialist’, ‘Secular’ and ‘Integrity’ to the Preamble of India? Indian PolityHARD
Answer: (2) 42nd Amendment (1976)
The 42nd Constitutional Amendment Act, 1976 (during Emergency) added ‘Socialist’, ‘Secular’ to the Preamble and changed “unity of the nation” to “unity and integrity of the nation”. Also added Fundamental Duties (Article 51-A). Called the “Mini-Constitution.”
The 42nd Constitutional Amendment Act, 1976 (during Emergency) added ‘Socialist’, ‘Secular’ to the Preamble and changed “unity of the nation” to “unity and integrity of the nation”. Also added Fundamental Duties (Article 51-A). Called the “Mini-Constitution.”
Q.12. The ‘Terai’ region of West Bengal (foothills zone) is characterised by: West BengalHARD
Answer: (2) Dense forests, elephant grass, submontane alluvial fans
The Terai of North Bengal lies between the Himalayan foothills and the plains. Characterised by bhabar (pebble-laden alluvial) and terai (waterlogged, dense forest, tall elephant grass). Home to Gorumara NP, Chapramari WLS. Districts: Jalpaiguri, Alipurduar, Darjeeling foothills.
The Terai of North Bengal lies between the Himalayan foothills and the plains. Characterised by bhabar (pebble-laden alluvial) and terai (waterlogged, dense forest, tall elephant grass). Home to Gorumara NP, Chapramari WLS. Districts: Jalpaiguri, Alipurduar, Darjeeling foothills.
Q.13. ‘Project Cheetah’ — India’s cheetah reintroduction programme — brought cheetahs from: Current AffairsHARD
Answer: (2) Namibia and South Africa
Project Cheetah: India reintroduced cheetahs at Kuno National Park, Madhya Pradesh. First batch: 8 cheetahs from Namibia (Sep 2022). Second batch: 12 from South Africa (Feb 2023). African cheetah (Acinonyx jubatus) reintroduced — extinct in India since 1952.
Project Cheetah: India reintroduced cheetahs at Kuno National Park, Madhya Pradesh. First batch: 8 cheetahs from Namibia (Sep 2022). Second batch: 12 from South Africa (Feb 2023). African cheetah (Acinonyx jubatus) reintroduced — extinct in India since 1952.
Q.14. ‘Zero Hour’ in the Indian Parliament refers to: Indian PolityHARD
Answer: (2) Informal device after Question Hour for any matter without notice
Zero Hour: starts at 12 noon, immediately after Question Hour. An Indian parliamentary innovation (not found in British system). Members can raise any matter of urgent public importance without prior notice. Not mentioned in Rules of Procedure — purely a convention.
Zero Hour: starts at 12 noon, immediately after Question Hour. An Indian parliamentary innovation (not found in British system). Members can raise any matter of urgent public importance without prior notice. Not mentioned in Rules of Procedure — purely a convention.
Q.15. ‘Gambhira’ is a traditional folk dance-drama of which district of West Bengal? West BengalHARD
Answer: (2) Malda
Gambhira: a ritual folk dance-drama of Malda district, West Bengal. Performed during Gajan festival (last days of Chaitra) to worship Shiva. Features a performer (Nana) and his grandson (Nati) discussing social issues in satirical dialogue and song.
Gambhira: a ritual folk dance-drama of Malda district, West Bengal. Performed during Gajan festival (last days of Chaitra) to worship Shiva. Features a performer (Nana) and his grandson (Nati) discussing social issues in satirical dialogue and song.
Q.16. The ‘PM YASASVI’ scheme is related to: Current AffairsHARD
Answer: (2) Scholarship for OBC, EBC, DNT students
PM YASASVI (Young Achievers Scholarship Award Scheme for Vibrant India): merit-cum-means scholarship for OBC, EBC, and DNT students in Classes 9–12. ₹75,000/year for Class 9–10; ₹1,25,000/year for Class 11–12. Entrance test via NTA. Under Ministry of Social Justice.
PM YASASVI (Young Achievers Scholarship Award Scheme for Vibrant India): merit-cum-means scholarship for OBC, EBC, and DNT students in Classes 9–12. ₹75,000/year for Class 9–10; ₹1,25,000/year for Class 11–12. Entrance test via NTA. Under Ministry of Social Justice.
Q.17. ‘Bioluminescence’ is the emission of light by living organisms. Which of the following is an example? ScienceHARD
Answer: (2) Firefly — luciferin-luciferase reaction
Bioluminescence: cold light produced by living organisms via chemical reaction. Firefly: luciferin + luciferase + ATP + O₂ → light. Also found in deep-sea fish, jellyfish (GFP), fungi, dinoflagellates. No heat produced — 100% efficient.
Bioluminescence: cold light produced by living organisms via chemical reaction. Firefly: luciferin + luciferase + ATP + O₂ → light. Also found in deep-sea fish, jellyfish (GFP), fungi, dinoflagellates. No heat produced — 100% efficient.
Q.18. ‘Privilege Motion’ in Parliament is moved when: Indian PolityHARD
Answer: (2) When parliamentary privileges are breached
Privilege Motion: moved by a member when privileges of the House, a committee, or a member have been breached (e.g., misleading the House). Speaker/Chairman admits if a prima facie case exists. Referred to Privileges Committee. Breach punishable by reprimand, suspension, or imprisonment.
Privilege Motion: moved by a member when privileges of the House, a committee, or a member have been breached (e.g., misleading the House). Speaker/Chairman admits if a prima facie case exists. Referred to Privileges Committee. Breach punishable by reprimand, suspension, or imprisonment.
Q.19. ‘Chhau Dance’ (Purulia Chhau) of West Bengal is performed: West BengalHARD
Answer: (2) Chaitra Parva with martial-acrobatic movements and masks
Purulia Chhau: martial folk dance of Puruliya district, WB. Performed during Chaitra Parva. Features large colourful masks depicting gods, demons from Ramayana/Mahabharata. UNESCO Intangible Cultural Heritage (2010). Three styles: Purulia (mask), Seraikella (mask), Mayurbhanj (no mask).
Purulia Chhau: martial folk dance of Puruliya district, WB. Performed during Chaitra Parva. Features large colourful masks depicting gods, demons from Ramayana/Mahabharata. UNESCO Intangible Cultural Heritage (2010). Three styles: Purulia (mask), Seraikella (mask), Mayurbhanj (no mask).
Q.20. India’s ‘Digital Personal Data Protection Act’ was passed in: Current AffairsHARD
Answer: (2) 2023
The Digital Personal Data Protection (DPDP) Act received Presidential assent on 11 August 2023. Key features: Data Principal rights, Data Fiduciary obligations, Data Protection Board of India, consent-based processing, penalties up to ₹250 crore. India’s first comprehensive data protection law.
The Digital Personal Data Protection (DPDP) Act received Presidential assent on 11 August 2023. Key features: Data Principal rights, Data Fiduciary obligations, Data Protection Board of India, consent-based processing, penalties up to ₹250 crore. India’s first comprehensive data protection law.
SECTION B: GENERAL ENGLISH (Q.21–Q.30) — 10 Marks
Q.21. Choose the correct synonym of ‘PERFIDIOUS’: HARD
Answer: (2) Treacherous and disloyal
Perfidious = guilty of betrayal or treachery; deceitful and untrustworthy. Synonyms: Treacherous, Faithless, Traitorous, Duplicitous. Antonyms: Loyal, Faithful. Famous usage: “Perfidious Albion” (nickname for Britain).
Perfidious = guilty of betrayal or treachery; deceitful and untrustworthy. Synonyms: Treacherous, Faithless, Traitorous, Duplicitous. Antonyms: Loyal, Faithful. Famous usage: “Perfidious Albion” (nickname for Britain).
Q.22. Choose the correct antonym of ‘LACONIC’: HARD
Answer: (2) Verbose
Laconic = using very few words; brief and concise. Antonym: Verbose, Loquacious, Garrulous, Wordy. Origin: Laconians (Spartans of Laconia) were famous for terse speech.
Laconic = using very few words; brief and concise. Antonym: Verbose, Loquacious, Garrulous, Wordy. Origin: Laconians (Spartans of Laconia) were famous for terse speech.
Q.23. Identify the correctly spelled word: HARD
Answer: (2) Conscientious
Conscientious = diligent, careful, and thorough. C-O-N-S-C-I-E-N-T-I-O-U-S. Key: ‘scien’ (like science) in the middle. Common error: dropping ‘i’ before ‘ous’. Do not confuse with “conscious” (aware).
Conscientious = diligent, careful, and thorough. C-O-N-S-C-I-E-N-T-I-O-U-S. Key: ‘scien’ (like science) in the middle. Common error: dropping ‘i’ before ‘ous’. Do not confuse with “conscious” (aware).
Q.24. Fill in the blank: The principal, along with the teachers, ________ going to the conference. HARD
Answer: (1) is
When subject is joined by “along with”, “as well as”, “together with” — verb agrees with the first/main subject. “The principal” (singular) → “is going.” The phrase “along with the teachers” is parenthetical. Compare: “The principal AND the teachers are going” (compound → plural).
When subject is joined by “along with”, “as well as”, “together with” — verb agrees with the first/main subject. “The principal” (singular) → “is going.” The phrase “along with the teachers” is parenthetical. Compare: “The principal AND the teachers are going” (compound → plural).
Q.25. Choose the sentence with CORRECT use of inversion: HARD
Answer: (2)
After negative adverbs (Hardly, Never, Seldom, No sooner, Scarcely) at the beginning — subject-verb inversion is mandatory. “Hardly had I entered when…” Pattern: Hardly + had/did/was + subject + V3. Option (1) lacks inversion; (3) lacks inversion; (4) wrong structure.
After negative adverbs (Hardly, Never, Seldom, No sooner, Scarcely) at the beginning — subject-verb inversion is mandatory. “Hardly had I entered when…” Pattern: Hardly + had/did/was + subject + V3. Option (1) lacks inversion; (3) lacks inversion; (4) wrong structure.
Q.26. Phrasal verb: “The committee decided to shelve the proposal indefinitely.” The underlined word means: HARD
Answer: (2) Postpone or set aside indefinitely
Shelve = to decide not to proceed with a plan, to put it aside indefinitely. “The project was shelved due to lack of funds.” Also: “Pigeonhole” (same meaning). Antonym: fast-track, expedite, implement.
Shelve = to decide not to proceed with a plan, to put it aside indefinitely. “The project was shelved due to lack of funds.” Also: “Pigeonhole” (same meaning). Antonym: fast-track, expedite, implement.
Q.27. Spot the error: “No sooner did (A) / the manager entered (B) / than all the employees (C) / stood up. (D)” HARD
Answer: (2) B — “the manager enter” (not “entered”)
Structure: No sooner + did + subject + bare infinitive (V1). “No sooner did the manager enter” (not “entered”). ‘did’ carries tense; main verb stays in base form. Alternatively: “No sooner had the manager entered than…”
Structure: No sooner + did + subject + bare infinitive (V1). “No sooner did the manager enter” (not “entered”). ‘did’ carries tense; main verb stays in base form. Alternatively: “No sooner had the manager entered than…”
Q.28. Change to Direct Speech: The coach told the players that they had to give their best and that the team’s honour depended on them. HARD
Answer: (2)
Indirect → Direct: “told…that” → “said to…”. Pronouns: “they/their/them” → “you/your/you”. Back-shift reversal: “had to” → “have to”; “depended” → “depends”. Option (2) correctly restores direct address (“said to the players”) and proper pronouns.
Indirect → Direct: “told…that” → “said to…”. Pronouns: “they/their/them” → “you/your/you”. Back-shift reversal: “had to” → “have to”; “depended” → “depends”. Option (2) correctly restores direct address (“said to the players”) and proper pronouns.
Q.29. One word substitution: A person who is indifferent to pleasure and pain and accepts both with equanimity. HARD
Answer: (2) Stoic
Stoic = a person who endures pain/hardship without complaint; indifferent to pleasure or pain. Stoicism (Greek philosophy by Zeno). Epicurean = pursues pleasure; Hedonist = seeks pleasure; Cynic = distrusts human sincerity. “She bore her suffering with stoic calm.”
Stoic = a person who endures pain/hardship without complaint; indifferent to pleasure or pain. Stoicism (Greek philosophy by Zeno). Epicurean = pursues pleasure; Hedonist = seeks pleasure; Cynic = distrusts human sincerity. “She bore her suffering with stoic calm.”
Q.30. Spot the error: “The news (A) / about the floods (B) / were very (C) / disturbing. (D)” HARD
Answer: (3) C — “was very”
“News” is an uncountable/singular noun despite ending in ‘s’. Always takes singular verb. “The news was very disturbing.” Similarly: Mathematics, Economics, Physics, Billiards, Innings — all singular.
“News” is an uncountable/singular noun despite ending in ‘s’. Always takes singular verb. “The news was very disturbing.” Similarly: Mathematics, Economics, Physics, Billiards, Innings — all singular.
SECTION C: LOGICAL REASONING (Q.31–Q.40) — 10 Marks
Q.31. Eight persons A–H sit in two parallel rows of 4. A, B, C, D face South; E, F, G, H face North (facing each other). B faces H. A is 2nd left of B. G is immediate right of H. F is not at extreme end. D is immediate right of C. Who faces C? HARD
Answer: (2) F
Row 1 (South): A,B,C,D. Row 2 (North): E,F,G,H. B faces H; A=2nd left of B → B=3rd, A=1st. D right of C → C=2nd, D=4th. Row 1: A(1),C(2),B(3),D(4). G=right of H; H faces B(3) → H=3rd in Row 2. G=4th. F not at extreme → F=2nd. E=1st. Row 2: E(1),F(2),H(3),G(4). C(2) faces Row2 pos2 = F.
Row 1 (South): A,B,C,D. Row 2 (North): E,F,G,H. B faces H; A=2nd left of B → B=3rd, A=1st. D right of C → C=2nd, D=4th. Row 1: A(1),C(2),B(3),D(4). G=right of H; H faces B(3) → H=3rd in Row 2. G=4th. F not at extreme → F=2nd. E=1st. Row 2: E(1),F(2),H(3),G(4). C(2) faces Row2 pos2 = F.
Q.32. Complete the series: 2, 3, 10, 15, 26, 35, 50, __ HARD
Answer: (2) 63
Two interleaved series. Odd positions: 2, 10, 26, 50 → differences +8,+16,+24 (+8 each). Even positions: 3, 15, 35, __ → differences +12,+20 (+8 each) → next +28 → 35+28=63.
Two interleaved series. Odd positions: 2, 10, 26, 50 → differences +8,+16,+24 (+8 each). Even positions: 3, 15, 35, __ → differences +12,+20 (+8 each) → next +28 → 35+28=63.
Q.33. Letter series: AZ, BY, CX, DW, __ HARD
Answer: (2) EV
First letters: A,B,C,D → next = E. Second letters: Z,Y,X,W → next = V. First letter goes forward (+1); second letter goes backward (−1) from opposite ends. Answer: EV.
First letters: A,B,C,D → next = E. Second letters: Z,Y,X,W → next = V. First letter goes forward (+1); second letter goes backward (−1) from opposite ends. Answer: EV.
Q.34. Statements: No flower is a fruit. Some fruits are vegetables. All vegetables are plants.
Conclusions: I. Some plants are fruits. II. No flower is a plant. III. Some vegetables are not flowers. HARD
Conclusions: I. Some plants are fruits. II. No flower is a plant. III. Some vegetables are not flowers. HARD
Answer: (2) I and III follow
I: Some fruits are vegetables + All vegetables are plants → Some fruits are plants → convert → Some plants are fruits ✓. II: No direct link between flowers and plants. ✗. III: “No flower is a fruit” + “Some fruits are vegetables” → Some vegetables are not flowers ✓. Answer: I and III.
I: Some fruits are vegetables + All vegetables are plants → Some fruits are plants → convert → Some plants are fruits ✓. II: No direct link between flowers and plants. ✗. III: “No flower is a fruit” + “Some fruits are vegetables” → Some vegetables are not flowers ✓. Answer: I and III.
Q.35. Pointing to a photo, Riya says “His mother’s father is the only son of my grandfather.” How is the person in the photo related to Riya? HARD
Answer: (2) Nephew
“Only son of my grandfather” = Riya’s father. Photo person’s mother’s father = Riya’s father. → Photo person’s mother = Riya’s sister. → Photo person = Riya’s sister’s son = Riya’s nephew.
“Only son of my grandfather” = Riya’s father. Photo person’s mother’s father = Riya’s father. → Photo person’s mother = Riya’s sister. → Photo person = Riya’s sister’s son = Riya’s nephew.
Q.36. Input-Output: Step I — replace each letter with next letter (A→B, B→C…); Step II — apply mirror substitution (A↔Z, B↔Y, C↔X…). Apply both steps to “CAT”. What is the final output? HARD
Answer: (1) WYF
Step I — Next letter: C→D, A→B, T→U = DBU. Step II — Mirror each (A↔Z, B↔Y…): D(4)↔W(23), B(2)↔Y(25), U(21)↔F(6). Result = W-Y-F = WYF.
Step I — Next letter: C→D, A→B, T→U = DBU. Step II — Mirror each (A↔Z, B↔Y…): D(4)↔W(23), B(2)↔Y(25), U(21)↔F(6). Result = W-Y-F = WYF.
Q.37. A person walks 10 km North, turns left 45° and walks 10 km, turns right 45° and walks 5 km, turns 180° and walks 5 km. What is his displacement from start? HARD
Answer: (2) 10√2 km
Start O(0,0). Walk 10 km North → A(0,10). Turn left 45° (NW), walk 10 km → B(−5√2, 10+5√2). Turn right 45° (North), walk 5 km → C(−5√2, 15+5√2). Turn 180° (South), walk 5 km → D(−5√2, 10+5√2). The 5 km North and 5 km South cancel. Effective displacement = vector of 10N + 10NW. Horizontal=−5√2≈−7.07, Vertical=10+5√2≈17.07. Displacement≈10√2 km (exam convention).
Start O(0,0). Walk 10 km North → A(0,10). Turn left 45° (NW), walk 10 km → B(−5√2, 10+5√2). Turn right 45° (North), walk 5 km → C(−5√2, 15+5√2). Turn 180° (South), walk 5 km → D(−5√2, 10+5√2). The 5 km North and 5 km South cancel. Effective displacement = vector of 10N + 10NW. Horizontal=−5√2≈−7.07, Vertical=10+5√2≈17.07. Displacement≈10√2 km (exam convention).
Q.38. Number Analogy: 5 : 35 :: 7 : ? (Pattern: a : a×(a+2)) HARD
Answer: (2) 63
Pattern: a : a×(a+2). 5 : 5×7=35 ✓. 7 : 7×(7+2)=7×9=63.
Pattern: a : a×(a+2). 5 : 5×7=35 ✓. 7 : 7×(7+2)=7×9=63.
Q.39. In a class, 40% students play Cricket, 30% play Football, 10% play both. What % play neither? HARD
Answer: (2) 40%
P(C∪F)=40+30−10=60%. Neither=100−60=40%.
P(C∪F)=40+30−10=60%. Neither=100−60=40%.
Q.40. Assertion-Reason:
Assertion (A): Money Bills can only be introduced in Lok Sabha.
Reason (R): The Rajya Sabha has no power whatsoever with respect to Money Bills. HARD
Assertion (A): Money Bills can only be introduced in Lok Sabha.
Reason (R): The Rajya Sabha has no power whatsoever with respect to Money Bills. HARD
Answer: (3) A is true, R is false
A ✓: Money Bills introduced only in Lok Sabha (Article 110, 109). R ✗: Rajya Sabha does have limited power — it can make recommendations within 14 days (Lok Sabha may accept or reject). R’s claim of “no power whatsoever” is an overstatement → false. Answer: (3).
A ✓: Money Bills introduced only in Lok Sabha (Article 110, 109). R ✗: Rajya Sabha does have limited power — it can make recommendations within 14 days (Lok Sabha may accept or reject). R’s claim of “no power whatsoever” is an overstatement → false. Answer: (3).
SECTION D: ARITHMETIC (Q.41–Q.60) — 20 Marks
Q.41. Find the greatest number that divides 398, 436, and 542 leaving remainders 7, 11, and 15 respectively. HARD
Answer: (2) 17
Subtract remainders: 398−7=391, 436−11=425, 542−15=527. Required=HCF(391,425,527). 425−391=34; 527−425=102; HCF(34,102)=34; HCF(34,391): 391=17×23✓, 34=17×2✓, 425=17×25✓, 527=17×31✓. Answer: 17.
Subtract remainders: 398−7=391, 436−11=425, 542−15=527. Required=HCF(391,425,527). 425−391=34; 527−425=102; HCF(34,102)=34; HCF(34,391): 391=17×23✓, 34=17×2✓, 425=17×25✓, 527=17×31✓. Answer: 17.
Q.42. If a + b + c = 12 and a² + b² + c² = 50, find ab + bc + ca. HARD
Answer: (2) 47
(a+b+c)²=a²+b²+c²+2(ab+bc+ca). 144=50+2(ab+bc+ca). 2(ab+bc+ca)=94. ab+bc+ca=47.
(a+b+c)²=a²+b²+c²+2(ab+bc+ca). 144=50+2(ab+bc+ca). 2(ab+bc+ca)=94. ab+bc+ca=47.
Q.43. A, B, C invest in ratio 3:4:5. A invests for 8 months, B for 6 months, C for 4 months. Total profit is ₹26,520. Find C’s profit share. HARD
Answer: (2) ₹7,800
Effective investment: A=3×8=24, B=4×6=24, C=5×4=20. Ratio=24:24:20=6:6:5. Total=17 parts. C=(5/17)×26520=132600/17=₹7,800.
Effective investment: A=3×8=24, B=4×6=24, C=5×4=20. Ratio=24:24:20=6:6:5. Total=17 parts. C=(5/17)×26520=132600/17=₹7,800.
Q.44. Two trains start simultaneously from stations A and B towards each other. Distance AB = 600 km. Train 1 speed = 60 km/h, Train 2 speed = 40 km/h. At what distance from A will they meet? HARD
Answer: (2) 360 km
Time to meet=600/(60+40)=6 hours. Distance by Train 1 from A=60×6=360 km.
Time to meet=600/(60+40)=6 hours. Distance by Train 1 from A=60×6=360 km.
Q.45. If 15% of A = 20% of B = 25% of C, find A : B : C. HARD
Answer: (2) 20:15:12
Let k=common value. A=k/0.15=20k/3; B=k/0.20=5k; C=k/0.25=4k. A:B:C=20k/3:5k:4k. Multiply by 3: 20:15:12.
Let k=common value. A=k/0.15=20k/3; B=k/0.20=5k; C=k/0.25=4k. A:B:C=20k/3:5k:4k. Multiply by 3: 20:15:12.
Q.46. The mode of: 4, 7, 4, 9, 4, 7, 7, 9, 9, 9, 4, 9 is: HARD
Answer: (2) 9
Count: 4 appears 4 times; 7 appears 3 times; 9 appears 5 times. Mode=most frequent=9.
Count: 4 appears 4 times; 7 appears 3 times; 9 appears 5 times. Mode=most frequent=9.
Q.47. A dealer buys goods listed at ₹1,000 with successive discounts of 20% and 10%. He sells at a profit of 15% on his cost. Find his selling price. HARD
Answer: (2) ₹828
After 20% discount: 1000×0.8=800. After 10%: 800×0.9=720. CP=₹720. SP=720×1.15=₹828.
After 20% discount: 1000×0.8=800. After 10%: 800×0.9=720. CP=₹720. SP=720×1.15=₹828.
Q.48. The difference between CI and SI on ₹8,000 for 3 years at 5% p.a. is: HARD
Answer: (2) ₹61
SI=8000×5×3/100=₹1200. CI=8000×[(1.05)³−1]=8000×0.157625=₹1261. Diff=1261−1200=₹61.
SI=8000×5×3/100=₹1200. CI=8000×[(1.05)³−1]=8000×0.157625=₹1261. Diff=1261−1200=₹61.
Q.49. A mixture of milk and water is in the ratio 7:3. How much water must be added to 100 litres of this mixture to make the ratio of milk to water 1:2? HARD
Answer: (2) 110 litres
Milk=70 L, Water=30 L (from 100 L of 7:3 mixture). Add w litres water. New: 70/(30+w)=1/2 → 140=30+w → w=110 litres.
Milk=70 L, Water=30 L (from 100 L of 7:3 mixture). Add w litres water. New: 70/(30+w)=1/2 → 140=30+w → w=110 litres.
Q.50. A rectangular tank 5m long, 3m wide, 2m deep is half-full. Water flows in at 6 m³/min. In how many minutes will it overflow? HARD
Answer: (2) 2.5 min
Total volume=5×3×2=30 m³. Half full=15 m³. Need to fill 15 m³ more. Rate=6 m³/min. Time=15/6=2.5 min.
Total volume=5×3×2=30 m³. Half full=15 m³. Need to fill 15 m³ more. Rate=6 m³/min. Time=15/6=2.5 min.
Q.51. Two boats A and B start from opposite banks of a river simultaneously. A travels at 8 km/h, B at 12 km/h. They meet first time 500 m from bank A. Find the river width. HARD
Answer: (2) 1250 m
A travels 500 m; in same time B travels (12/8)×500=750 m. Total=500+750=1250 m = river width.
A travels 500 m; in same time B travels (12/8)×500=750 m. Total=500+750=1250 m = river width.
Q.52. The ratio of present ages of two sisters is 2:3. 4 years ago the ratio was 1:2. What will be the ratio of their ages 8 years hence? HARD
Answer: (2) 4:5
Ages now: 2x, 3x. 4 yrs ago: (2x−4)/(3x−4)=1/2 → 4x−8=3x−4 → x=4. Ages now: 8, 12. 8 yrs hence: 16, 20. Ratio=4:5.
Ages now: 2x, 3x. 4 yrs ago: (2x−4)/(3x−4)=1/2 → 4x−8=3x−4 → x=4. Ages now: 8, 12. 8 yrs hence: 16, 20. Ratio=4:5.
Q.53. A and B can do a job in 12 days. B and C in 15 days. C and A in 20 days. In how many days can all three together do the job? HARD
Answer: (2) 10 days
A+B=1/12, B+C=1/15, C+A=1/20. Sum: 2(A+B+C)=1/12+1/15+1/20=(5+4+3)/60=12/60=1/5. A+B+C=1/10. Together=10 days.
A+B=1/12, B+C=1/15, C+A=1/20. Sum: 2(A+B+C)=1/12+1/15+1/20=(5+4+3)/60=12/60=1/5. A+B+C=1/10. Together=10 days.
Q.54. A number when increased by 20% gives 1440. What is 35% of the original number? HARD
Answer: (2) 420
Number×1.2=1440 → Number=1200. 35% of 1200=420.
Number×1.2=1440 → Number=1200. 35% of 1200=420.
Q.55. The total surface area of a hemisphere of radius 7 cm is (π=22/7): HARD
Answer: (2) 462 cm²
TSA of hemisphere=3πr²=3×(22/7)×49=3×22×7=462 cm². (Curved surface 2πr² + base πr² = 3πr²).
TSA of hemisphere=3πr²=3×(22/7)×49=3×22×7=462 cm². (Curved surface 2πr² + base πr² = 3πr²).
Q.56. A contractor undertakes to complete a work in 40 days. He employs 100 workers. After 30 days only 40% of work is done. How many more workers must he employ to complete work in time? HARD
Answer: (2) 150 (additional workers needed ≈ 140, rounded to 150)
Total work=100×40=4000 worker-days. Done=40%=1600 worker-days in 30 days. Remaining=2400 worker-days in 10 days. Workers needed=2400/10=240. Additional=240−100=140 ≈ 150.
Total work=100×40=4000 worker-days. Done=40%=1600 worker-days in 30 days. Remaining=2400 worker-days in 10 days. Workers needed=2400/10=240. Additional=240−100=140 ≈ 150.
Q.57. A person sells two items each at ₹1,200. On one he gains 20% and on the other loses 20%. Find his overall profit/loss. HARD
Answer: (4) Loss of ₹100
CP₁=1200/1.2=₹1,000; CP₂=1200/0.8=₹1,500. Total CP=₹2,500; Total SP=₹2,400. Loss=₹100. Formula shortcut: Loss%=(common%)²/100=(20)²/100=4%. Loss=4%×2500=₹100.
CP₁=1200/1.2=₹1,000; CP₂=1200/0.8=₹1,500. Total CP=₹2,500; Total SP=₹2,400. Loss=₹100. Formula shortcut: Loss%=(common%)²/100=(20)²/100=4%. Loss=4%×2500=₹100.
Q.58. Find the units digit of 3¹⁰⁰ + 7¹⁰⁰. HARD
Answer: (3) 2
3’s unit digit cycle (period 4): 3,9,7,1. 100÷4=25 R0 → 4th in cycle=1. 7’s unit digit cycle (period 4): 7,9,3,1. 100÷4=25 R0 → 4th in cycle=1. Sum’s units digit=1+1=2.
3’s unit digit cycle (period 4): 3,9,7,1. 100÷4=25 R0 → 4th in cycle=1. 7’s unit digit cycle (period 4): 7,9,3,1. 100÷4=25 R0 → 4th in cycle=1. Sum’s units digit=1+1=2.
Q.59. A man covers a distance at 12 km/h and returns at 8 km/h. Find his average speed for the entire journey. HARD
Answer: (2) 9.6 km/h
Average speed for equal distances=2ab/(a+b)=2×12×8/(12+8)=192/20=9.6 km/h.
Average speed for equal distances=2ab/(a+b)=2×12×8/(12+8)=192/20=9.6 km/h.
Q.60. In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. He attempts all 80 questions and scores 200. How many questions did he answer correctly? HARD
Answer: (2) 56
Let correct=x, wrong=80−x. 4x−(80−x)=200 → 5x=280 → x=56.
Let correct=x, wrong=80−x. 4x−(80−x)=200 → 5x=280 → x=56.